document.write( "Question 697245: Kx^2+kx+5=0 what is the value of \"k\" \n" ); document.write( "
Algebra.Com's Answer #429880 by MathLover1(20850)\"\" \"About 
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\"kx%5E2%2Bkx%2B5=0+\"\r
\n" ); document.write( "\n" ); document.write( "If the discriminant \"b%5E2+-+4ac+=+0\", then the solution will have equal roots or only one solution\r
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\n" ); document.write( "\n" ); document.write( "here \"b+=+k\"
\n" ); document.write( "\"a+=+k\"
\n" ); document.write( "\"c+=+5\"\r
\n" ); document.write( "\n" ); document.write( "so\r
\n" ); document.write( "\n" ); document.write( "\"k%5E2+-+4%2Ak%2A5+=+0\"\r
\n" ); document.write( "\n" ); document.write( "\"k%5E2+-+20k+=+0\"\r
\n" ); document.write( "\n" ); document.write( "\"k%28k+-+20%29+=+0\"...since \"k%3C%3E0\" product will be equal to zero if \r
\n" ); document.write( "\n" ); document.write( "\"k+-+20=0\"\r
\n" ); document.write( "\n" ); document.write( "so\r
\n" ); document.write( "\n" ); document.write( "\"k+=20\"\r
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\n" ); document.write( "\n" ); document.write( "then you have:\r
\n" ); document.write( "\n" ); document.write( "\"20x%5E2%2B20x%2B5=0+\"\r
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\n" ); document.write( "\n" ); document.write( "check if the roots are equal:\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-20+%2B-+sqrt%2820%5E2-4%2A20%2A5+%29%29%2F%282%2A20%29+\"\r
\n" ); document.write( "\n" ); document.write( "\"x+=+%28-20+%2B-+sqrt%28400-400+%29%29%2F40+\"\r
\n" ); document.write( "\n" ); document.write( "\"x+=+%28-20+%2B-+sqrt%280%29%29%2F40+\"\r
\n" ); document.write( "\n" ); document.write( "\"x+=+%28-20+%2B-+0%29%2F40+\"\r
\n" ); document.write( "\n" ); document.write( "\"x+=+-20%2F40+\"\r
\n" ); document.write( "\n" ); document.write( "\"x+=+-1%2F2+\".......so, we have only one root\r
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\n" ); document.write( "\n" ); document.write( "see it on a graph:\r
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\n" ); document.write( "\n" ); document.write( "\"+graph%28+600%2C+600%2C+-5%2C+5%2C+-5%2C+5%2C+20x%5E2%2B20x%2B5%29+\"\r
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