document.write( "Question 62132: Factor completely 12x^3-3xy^2 \n" ); document.write( "

Algebra.Com's Answer #42987 by 303795(602) $\"\"$ $\"About$

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Look for common factors in each term. eg 12 and 3 have a common factor of 3\r
\n" ); document.write( "\n" ); document.write( " $\"12x%5E3-3xy%5E2+\"$ Take the common factor 3 out the front of the expression
\n" ); document.write( " $\"3%284x%5E3-xy%5E2%29+\"$ A common factor x can also be taken out the front of the brackets
\n" ); document.write( " $\"3x%284x%5E2-y%5E2%29+\"$ Now look at the terms in the brackets.
\n" ); document.write( "This is a difference of squares $\"4x%5E2-y%5E2+=+%282x%29%5E2+-+y%5E2+=+%282x+%2B+y%29%282x+-+y%29\"$ \r
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\n" ); document.write( "\n" ); document.write( "So the final factorised solution is $\"12x%5E3-3xy%5E2+=+3x%282x+%2B+y%29%282x+-+y%29+\"$ \n" ); document.write( "

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