document.write( "Question 697214: For the polynomial below, -1 is a zero. \r
\n" ); document.write( "\n" ); document.write( "f(x)=x^3 +5x^2 +17x +13\r
\n" ); document.write( "\n" ); document.write( "Express f(x) as a product of linear factors. \r
\n" ); document.write( "\n" ); document.write( "f(x)= ?
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Algebra.Com's Answer #429850 by mouk(232)\"\" \"About 
You can put this solution on YOUR website!
\"+f%28x%29=x%5E3+%2B5x%5E2+%2B17x+%2B13+\"\r
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\n" ); document.write( "\n" ); document.write( "If x=-1 is a root then \"+%28x%2B1%29+\" is a factor so
\n" ); document.write( "\"+f%28x%29=%28x%2B1%29%28ax%5E2+%2B+bx+%2Bc%29+\"\r
\n" ); document.write( "\n" ); document.write( "By observation we can see the coefficient of \"+x%5E3+\" is 1 so \"+a+=+1+\" so:
\n" ); document.write( "\"+f%28x%29=%28x%2B1%29%28x%5E2+%2B+bx+%2Bc%29+\"
\n" ); document.write( "\"+f%28x%29=%28x%5E3+%2B+bx%5E2+%2Bcx%29+%2B+%28x%5E2+%2B+bx+%2Bc%29+\"
\n" ); document.write( "\"+f%28x%29=x%5E3+%2B+%28b%2B1%29x%5E2+%2B+%28c%2Bb%29x+%2B+c+\"\r
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\n" ); document.write( "\n" ); document.write( "Comparing coefficients of \"+x%5E0+\" : \"+c=13+\"
\n" ); document.write( "Comparing coefficients of \"+x%5E2+\" : \"+b%2B1=5+\" so \"+b=4+\"
\n" ); document.write( "Comparing coefficients of \"+x%5E1+\" : \"+c%2Bb=17+\" and is consistent with above\r
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\n" ); document.write( "\n" ); document.write( "Hence,
\n" ); document.write( "\"+f%28x%29=%28x%2B1%29%28x%5E2+%2B+4x+%2B+13%29+\"\r
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\n" ); document.write( "\n" ); document.write( "This does not factorize further
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