document.write( "Question 697276: A father is twice as old as son now. If father is 5/3 times the age of son after 10 years, find their present ages.
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Algebra.Com's Answer #429848 by josmiceli(19441)\"\" \"About 
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Let \"+f+\" = Father's age now
\n" ); document.write( "Let \"+s+\" = Son's age now
\n" ); document.write( "\"+f+%2B+10+\" = Father's age in 10 years
\n" ); document.write( "\"+s+%2B+10+\" = Son's age in 10 years
\n" ); document.write( "given:
\n" ); document.write( "(1) \"+f+=+2s+\"
\n" ); document.write( "(2) \"+f+%2B+10+=+%285%2F3%29%2A%28+s+%2B+10+%29+\"
\n" ); document.write( "----------------------------
\n" ); document.write( "(2) \"+f+%2B+10+=+%285%2F3%29%2As+%2B+50%2F3+\"
\n" ); document.write( "Substitute (1) into (2)
\n" ); document.write( "(2) \"+2s+%2B+10+=+%285%2F3%29%2As+%2B+50%2F3+\"
\n" ); document.write( "(2) \"+6s+%2B+30+=+5s+%2B+50+\"
\n" ); document.write( "(2) \"+s+=+50+-+30+\"
\n" ); document.write( "(2) \"+s+=+20+\"
\n" ); document.write( "and, since,
\n" ); document.write( "(1) \"+f+=+2s+\"
\n" ); document.write( "(1) \"+f+=+2%2A20+\"
\n" ); document.write( "(1) \"+f+=+40+\"
\n" ); document.write( "The Father is 40 and
\n" ); document.write( "The Son is 20
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\n" ); document.write( "check:
\n" ); document.write( "(2) \"+f+%2B+10+=+%285%2F3%29%2A%28+s+%2B+10+%29+\"
\n" ); document.write( "(2) \"+40+%2B+10+=+%285%2F3%29%2A%28+20+%2B+10+%29+\"
\n" ); document.write( "(2) \"+50+=+%285%2F3%29%2A30+\"
\n" ); document.write( "(2) \"+50+=+50+\"
\n" ); document.write( "OK\r
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