document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=697233>Question 697233</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a rectangle has one side equal to(2x+4)cm and a perimeter of (6x+4)cm.what is the area of the rectangle in terms of x? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #429781 by </B><A HREF=/tutors/aboutme.mpl?userid=mathbird><B>mathbird(71)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mathbird><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=429781\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> one side equal to(2x+4)cm<BR>\n" );
document.write( "perimeter of (6x+4)cm<BR>\n" );
document.write( "formula of perimeter of rectangle=2(length + breadth)<BR>\n" );
document.write( "(6x+4)=2{(2x+4)+breadth}<BR>\n" );
document.write( "2(3x+2)=2{(2x+4)+breadth}<BR>\n" );
document.write( "dividing by 2 on both sides<BR>\n" );
document.write( "3x+2=2x+4+breadth<BR>\n" );
document.write( "3x+2-2x-4=breadth<BR>\n" );
document.write( "x-2=breadth<BR>\n" );
document.write( "now;formula of area of rectangle = length *breadth<BR>\n" );
document.write( "=(2x+4)*(x-2)<BR>\n" );
document.write( "if need more simplification <BR>\n" );
document.write( "=>2x^2-4x+4x-8<BR>\n" );
document.write( "=2x^2-8 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );