document.write( "Question 62247: I cant remember how to start this question:\r
\n" ); document.write( "\n" ); document.write( "1-49/x^2
\n" ); document.write( "________
\n" ); document.write( "7/x+1\r
\n" ); document.write( "\n" ); document.write( "should I multiply each side by the inverse of the denominator?
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Algebra.Com's Answer #42978 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
1-49/x^2
\n" ); document.write( "________
\n" ); document.write( "7/x+1
\n" ); document.write( "--------------
\n" ); document.write( "[1-(49/x^2)]/[7/(x+1)]
\n" ); document.write( "Simplify the numerator:
\n" ); document.write( "[(x^2)-49)/x^2]/[7/(x+1)]
\n" ); document.write( "Invert the denominator and multiply:
\n" ); document.write( "[(x^2)-49)/x^2]
\n" ); document.write( "There are no common factors you can cancel.
\n" ); document.write( "So, multiply the numerators and the denominators as is:
\n" ); document.write( "[(x^2-49)(x+1)]/7x^2]
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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