document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=697140>Question 697140</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A collection of 24 coins worth 25c, P1, and P5 amounts to P36.25. If number of P1 is 3 more than thrice the number of P1, how many P5 are there? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #429733 by </B><A HREF=/tutors/aboutme.mpl?userid=god2012><B>god2012(113)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=god2012><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=god2012><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=429733\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Solution:\r<BR>\n" );
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document.write( "Let x be the number of P1 coins,<BR>\n" );
document.write( "y be the number of P5 coins<BR>\n" );
document.write( "z be the number of P25c coins.\r<BR>\n" );
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document.write( "x+y+z  = 24  ------------eq.1<BR>\n" );
document.write( "x = 3+3y     ------------eq.2\r<BR>\n" );
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document.write( "put 2 in 1,\r<BR>\n" );
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document.write( "3+3y+y+z = 24  = 3+4y+z<BR>\n" );
document.write( "4y+z = 21 ---------------eq.4<BR>\n" );
document.write( "But z = 1, that is, one 25c coin.<BR>\n" );
document.write( "y = 5\r<BR>\n" );
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document.write( "x  = 3 +15 = 18\r<BR>\n" );
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document.write( "z = 1\r<BR>\n" );
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document.write( " </SPAN>\n" );
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