document.write( "Question 697108: Hello
\n" ); document.write( "Please help me dividing these polynomials
\n" ); document.write( "(a^3+b^3+c^3-3abc)/(a+b+c)
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Algebra.Com's Answer #429701 by god2012(113)\"\" \"About 
You can put this solution on YOUR website!
Given : (a^3+b^3+c^3-3abc)/(a+b+c)\r
\n" ); document.write( "\n" ); document.write( "(a^3+b^3+c^3-3abc) can be written as (a+b+c)(a^2+b^2+c^2-(ab+bc+ac))\r
\n" ); document.write( "\n" ); document.write( "Therefore : (a^3+b^3+c^3-3abc)/(a+b+c) = (a^2+b^2+c^2-(ab+bc+ac))\r
\n" ); document.write( "\n" ); document.write( "Method 2 : a+b+c )a^3+b^3+c^3-3abc(a^2+b^2+c^2-ab-bc-ac
\n" ); document.write( " a^3+a^2b+a^2c subtract
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\n" ); document.write( " b^3+c^3-a^2b-a^2c-3abc
\n" ); document.write( " b^3+ab^2+cb^2 subtract
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\n" ); document.write( " c^3-a^2b-ab^2-a^2c-cb^2-3abc
\n" ); document.write( " c^3+c^2b+c^2a subtract
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\n" ); document.write( " -a^2b-ab^2-a^2c-cb^2-3abc-c^2b-c^2a
\n" ); document.write( " -a^2b-ab^2-abc subtract
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\n" ); document.write( " -a^2c-cb^2-2abc-c^2b-c^2a
\n" ); document.write( " -abc -b^2c-bc^2 subtract
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\n" ); document.write( " -a^2c-abc+ca^2
\n" ); document.write( " - a^2c-abc-ac^2 subtract
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\n" ); document.write( " 0\r
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\n" ); document.write( "\n" ); document.write( "Quotient = a^2+b^2+c^2-ab-bc-ac\r
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