document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=48604>Question 48604</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a coin collector has $45 in quarters and dimes.  How many coins of each does he have is the total number of his coins is 240? \r<BR>\n" );
document.write( "\n" );
document.write( "Thank you very much! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #42968 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=42968\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x=Number of dimes<BR>\n" );
document.write( "Then 240-x=Number of quarters\r<BR>\n" );
document.write( "\n" );
document.write( "Note:  Whatever monetary units we deal in (pennies, nickels, dollars, etc.), we have to be consistent. I choose to deal in pennies.\r<BR>\n" );
document.write( "\n" );
document.write( "Now we know that the amount of money in dimes (x)(10) plus the amount of money in quarters (240-x)(25)equals the total amount of money (4500).  Thus, our equation to solve is:<BR>\n" );
document.write( "10x+(240-x)(25)=4500 simplifying, we get:<BR>\n" );
document.write( "10x+6000-25x=4500 or<BR>\n" );
document.write( "-15x=-6000+4500=-1500<BR>\n" );
document.write( "x=100 dimes<BR>\n" );
document.write( "240-x=240-100=140 quarters\r<BR>\n" );
document.write( "\n" );
document.write( "Hope this helps ----ptaylor\r<BR>\n" );
document.write( "\n" );
document.write( " \r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );