document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=697106>Question 697106</A>: <I><SPAN STYLE=\"word-break: break-all;\"> John made a cubical lantern. The total length of its edges is 36 dm. What is the total surface area that he has to cover? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #429674 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=429674\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> John made a cubical lantern.<BR>\n" );
document.write( " The total length of its edges is 36 dm.<BR>\n" );
document.write( " What is the total surface area that he has to cover?<BR>\n" );
document.write( ":<BR>\n" );
document.write( "A cube has 12 edges, therefore one edge: 36/12 = 3 dm<BR>\n" );
document.write( ":<BR>\n" );
document.write( "A cube has 6 sides, therefore: <BR>\n" );
document.write( "Surface area of a cubes 6 time the area of each side<BR>\n" );
document.write( "S.A. = 6 * 3^2<BR>\n" );
document.write( "S.A. = 54 sq/dm<BR>\n" );
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