document.write( "Question 697090: solve the following algebraically:
\n" ); document.write( "\"2%2F%28x-3%29%2B4=2%2F%28x-3%29\"\r
\n" ); document.write( "\n" ); document.write( "I see that both sides of the equation have a \"2%2F%28x-3%29\" the only exception is the +4. I'm not sure what I am supposed to do with the four. Should I put a one under it? I don't understand how I am supposed to solve for \"x\"
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Algebra.Com's Answer #429651 by MathLover1(20849)\"\" \"About 
You can put this solution on YOUR website!
\"2%2F%28x-3%29%2B4=2%2F%28x-3%29\"...as you can see you have \"2%2F%28x-3%29\" on both sides; it will be same number for any \"x\" except \"x=3\" because \"x=3\" will make denominator \"x-3\" equal to zero and divide by zero doesn't make sense\r
\n" ); document.write( "\n" ); document.write( "since you have \"4\" only on left side, we can tell that \"2%2F%28x-3%29%2B4%3C%3E2%2F%28x-3%29\", and there is no solution for \"x\" that will make it equal\r
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