document.write( "Question 697079: Not so much a homework problem as an actual thing I'm grappling with in a gaming group. Your help would be much appreciated!\r
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document.write( "Four ten-sided dice are rolled. Each die that shows a 6 or lower is a \"success\", so the chance of a success is 60%, and the chance of a failure is 40%.\r
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document.write( "The chance of four successes is 0.6^4, or .1296 (12.96%), and the chance of four failures is 0.4^4, or .0256 (2.56%).\r
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document.write( "What are the chances of exactly one success, exactly two successes, and exactly three successes? \n" );
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Algebra.Com's Answer #429645 by stanbon(75887) ![]() You can put this solution on YOUR website! Four ten-sided dice are rolled. Each die that shows a 6 or lower is a \"success\", so the chance of a success is 60%, and the chance of a failure is 40%. \n" ); document.write( "The chance of four successes is 0.6^4, or .1296 (12.96%), and the chance of four failures is 0.4^4, or .0256 (2.56%). \n" ); document.write( "What are the chances of exactly one success, exactly two successes, and exactly three successes? \n" ); document.write( "-------- \n" ); document.write( "Binomial Problem with n = 4 ; p(1<= x <=6) = 0.6 \n" ); document.write( "---------- \n" ); document.write( "P(1 success) = 4C1(0.6)(0.4)^3 = 4*0.6*0.064 = 0.1536 \n" ); document.write( "----- \n" ); document.write( "P(2 successes) 4C2(0.6)^2(0.4)^2 = 6*0.36*0.16 = 0.3456 \n" ); document.write( "------------ \n" ); document.write( "P(3 successes) = 4C3(0.6)^3(0.4) = 4*0.216*0.4 = 0.3456 \n" ); document.write( "======================= \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "======================= \n" ); document.write( " \n" ); document.write( " |