document.write( "Question 696996: Two APs have the same common difference.The difference between their 100th term is100, what is the difference between their 1000th term? \n" ); document.write( "
Algebra.Com's Answer #429563 by god2012(113)\"\" \"About 
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Let the first AP is represented as TA = a1 + (n1-1)d , where a is the first term and d is the common difference , n1 is the number of terms in AP1.
\n" ); document.write( "Let the second AP be represented as TB = a2 + (n2-1)d.\r
\n" ); document.write( "\n" ); document.write( "Now ,\r
\n" ); document.write( "\n" ); document.write( "100th term of TA is TA100 = a1 + 99d
\n" ); document.write( "Similarly, 100th term of TB is TB100 = a2+99d\r
\n" ); document.write( "\n" ); document.write( "\"TB100-TA100+=+%28a2-a1%29+=+100\"\r
\n" ); document.write( "\n" ); document.write( "Therefore , \"TA1000+-+TB1000+=+%28a2%2B999d%29-%28a1%2B999d%29\"
\n" ); document.write( "The difference is \"%28a2-a1%29+=+100\"
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