document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=696972>Question 696972</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A rectangular photograph is twice as long as it is<BR>\n" );
document.write( "wide. The perimeter of the photograph is 84 cm.<BR>\n" );
document.write( "Find the length and the width of the photograph. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #429551 by </B><A HREF=/tutors/aboutme.mpl?userid=algebrahouse.com><B>algebrahouse.com(1659)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=algebrahouse.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=algebrahouse.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=429551\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x = width<BR>\n" );
document.write( "2x = length   {twice as long as it is wide}\r<BR>\n" );
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document.write( "Perimeter of a rectangle is 2(width) + 2(length)\r<BR>\n" );
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document.write( "2x + 2(2x) = 84   {perimeter is 2(width) + 2(length)<BR>\n" );
document.write( "2x + 4x = 84   {multiplied}<BR>\n" );
document.write( "6x = 84   {combined like terms}<BR>\n" );
document.write( "x = 14   {divided each side by 6}<BR>\n" );
document.write( "2x = 28   {substituted 14, in for x, into 2x}\r<BR>\n" );
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document.write( "width = 14 cm<BR>\n" );
document.write( "length = 28 cm<BR>\n" );
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