document.write( "Question 62233: (1/3)log₂(x+6) = log₈3x \n" ); document.write( "

Algebra.Com's Answer #42952 by kapilsinghi(68) $\"\"$ $\"About$

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(1/3)log₂(x+6) = log₈3x\r
\n" ); document.write( "\n" ); document.write( "=> (1/3)log₂(x+6) = (log₂3x)/(log₂8)
\n" ); document.write( "=> (1/3)log₂(x+6) = (log₂3x)/3*(log₂2)
\n" ); document.write( "=> (1/3)log₂(x+6) = (1/3)(log₂3x)
\n" ); document.write( "=> log₂(x+6) = (log₂3x)
\n" ); document.write( "Taking antilog on both sides
\n" ); document.write( "=> (x+6) = 3x
\n" ); document.write( "=> 2x = 6
\n" ); document.write( "=> x = 3\r
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