document.write( "Question 696910: Find three consecutive even integers such that when the first integer is multiplied by the third integer, the result is 2 more than 5 times the second integer. (only in algebraic solution) \n" ); document.write( "

Algebra.Com's Answer #429486 by stanbon(75887) $\"\"$ $\"About$

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Find three consecutive even integers such that when the first integer is multiplied by the third integer, the result is 2 more than 5 times the second integer.
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\n" ); document.write( "1st: 2x-2
\n" ); document.write( "2nd: 2x
\n" ); document.write( "3rd: 2x+2
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\n" ); document.write( "Equation:
\n" ); document.write( "(2x-2)(2x+2) = 5(2x)+2
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\n" ); document.write( "4x^2-4 = 10x + 2
\n" ); document.write( "4x^2 - 10x -6 = 0
\n" ); document.write( "---
\n" ); document.write( "2x^2 -5x -3 = 0
\n" ); document.write( "(2x+1)(x-3) = 0
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\n" ); document.write( "Positive solution:
\n" ); document.write( "x = 3
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\n" ); document.write( "1st: 2x-2 = 4
\n" ); document.write( "2nd: 6
\n" ); document.write( "3rd: 8
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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