document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=696905>Question 696905</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A 3 gallon mixture contain 1 part x and 2 parts y. In order to change it to a mixture containing 25%x, how much y should be added. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #429463 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=429463\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let A=amount of y that should be added:<BR>\n" );
document.write( "The 3 gallon mixture initially contains 1/3 x and 2/3 y<BR>\n" );
document.write( "Now we know that the amount of pure x that exists before the y is added ((1/3)*3) has to equal the amount of pure x that exists after the y is added (3+A)(1/4)<BR>\n" );
document.write( "Sooooo<BR>\n" );
document.write( "(1/3)*3=(1/4)*(3+A)<BR>\n" );
document.write( "1=3/4 + (1/4)*A<BR>\n" );
document.write( "1-(3/4)=(1/4)A<BR>\n" );
document.write( "1/4=(1/4)A<BR>\n" );
document.write( "A=1---gal of y needs to be added<BR>\n" );
document.write( "CK<BR>\n" );
document.write( "(1/3)*3=(1/4)*4<BR>\n" );
document.write( "1=1\r<BR>\n" );
document.write( "\n" );
document.write( "Hope this helps----ptaylor </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );