document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=696899>Question 696899</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A man rowing a boat away from a lighthouse 150m high takes 2 min to change the angle of elevation of the top of the lighthouse from 45 to 30 degree. find the speed of the boat. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #429461 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=429461\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A man rowing a boat away from a lighthouse 150m high takes 2 min to change the angle of elevation of the top of the lighthouse from 45 to 30 degree. find the speed of the boat.<BR>\n" );
document.write( "------------------<BR>\n" );
document.write( "His distance from the base = 150/tan<BR>\n" );
document.write( "d1 = 150/1<BR>\n" );
document.write( "d2 = 150/tan(30) = 150*sqrt(3) = 260 m<BR>\n" );
document.write( "d2-d1 = 110 meters<BR>\n" );
document.write( "r = 110/2 = 55 meters/min </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );