document.write( "Question 696725: A rectangle is such that the lengths of its adjacent sides differ by 5cm. A similar rectangle measures 18cm by 28cm. Find the length and breadth of the first rectangle. \n" ); document.write( "
Algebra.Com's Answer #429405 by KMST(5328)\"\" \"About 
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\"x\" = width of the first rectangle
\n" ); document.write( "\"x%2B5\" = length of the first rectangle
\n" ); document.write( "\"%28x%2B5%29%2Fx=28%2F18\" --> \"18%28x%2B5%29=28x\" --> \"18x%2B90=28x\" --> \"18x%2B90-18x=28x-18x\" --> \"90=10x\" --> \"90%2F10=10x%2F10\" --> \"highlight%28x=9%29\"
\n" ); document.write( "\"x%2B5=9%2B5\" --> \"x%2B5=14\" --> length of the first rectangle = \"highlight%2814%29\"
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\n" ); document.write( "Actually, for mental math, the ratio of corresponding sides is the same and also equal to the ratio of the differences in length, so I mentally calculated
\n" ); document.write( "\"x%2F18=5%2F%2828-18%29=5%2F10=1%2F2\" and immediately knew that the dimensions of the first rectangle were half of the dimensions of the other one.
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