document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=62201>Question 62201</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find 3 consecutive numbers whose sum is 126 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #42937 by </B><A HREF=/tutors/aboutme.mpl?userid=hotrodd><B>hotrodd(18)</B></A><img src=\"/images/stars/stars-06.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=hotrodd><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=42937\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (x) + (x + 1) + (x + 2) = 126<BR>\n" );
document.write( "we first made an equation to fit the problem. Do you see how each parenthesis is a number and how they are consecutive?<BR>\n" );
document.write( "Then we combine like terms.<BR>\n" );
document.write( "3x + 3 = 126<BR>\n" );
document.write( "Subtract each side by 3<BR>\n" );
document.write( "3x = 123<BR>\n" );
document.write( "Divide each side by 3<BR>\n" );
document.write( "x = 41\r<BR>\n" );
document.write( "\n" );
document.write( "SO YOUR ANSWER IS 41, 42, 43 </SPAN>\n" );
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