document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=62204>Question 62204</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0130504866/algebrahomeworkh>Pre-algenbra</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> what is  the three consecutive numbers whose sum is 126? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #42936 by </B><A HREF=/tutors/aboutme.mpl?userid=303795><B>303795(602)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=303795><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=42936\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If the three numbers are consecutive then call the first number x. The number after x will be (x + 1) and the number after that will be (x + 2). To find the sum then add the three numbers up.\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+%2B+%28x+%2B1%29+%2B+%28x+%2B+2%29+=+126 ALIGN=MIDDLE  ALT=\"x+%2B+%28x+%2B1%29+%2B+%28x+%2B+2%29+=+126\"   DISABLED_style= \"max-width:90%; height:auto;\" > \r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+%2B+x+%2B+1+%2B+x+%2B+2+=+126 ALIGN=MIDDLE  ALT=\"x+%2B+x+%2B+1+%2B+x+%2B+2+=+126\"   DISABLED_style= \"max-width:90%; height:auto;\" > Add like terms<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3x+%2B+3+=+126 ALIGN=MIDDLE  ALT=\"3x+%2B+3+=+126\"   DISABLED_style= \"max-width:90%; height:auto;\" > Subtract 3 from each side of the equation<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3x+%2B+3+-+3+=+126+-+3 ALIGN=MIDDLE  ALT=\"3x+%2B+3+-+3+=+126+-+3\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3x++=+123 ALIGN=MIDDLE  ALT=\"3x++=+123\"   DISABLED_style= \"max-width:90%; height:auto;\" > Divide each side of the equation by 3<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3x+%2F3++=+123%2F3 ALIGN=MIDDLE  ALT=\"3x+%2F3++=+123%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "x = 41\r<BR>\n" );
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document.write( "So the three numbers are 41, 42 and 43. Check that they add to 126.<BR>\n" );
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