document.write( "Question 696815: George Washington was born 11 years before Thomas Jefferson. In 1770 Washington's age was 3 more than 7 times the age of Jefferson in 1748. What was the sum of the two men's ages in 1750? \n" ); document.write( "
Algebra.Com's Answer #429341 by god2012(113)\"\" \"About 
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Solution :\r
\n" ); document.write( "\n" ); document.write( "Let G be the age of George Washington and T be the age of Thomas in the year 1748.\r
\n" ); document.write( "\n" ); document.write( "George was born 11 years before Thomas.
\n" ); document.write( "Therefore , G = T + 11 always.\r
\n" ); document.write( "\n" ); document.write( "In 1770, let the age of George be X and that of Thomas be Y,\r
\n" ); document.write( "\n" ); document.write( "Now, X = G+22 , Y = T + 22
\n" ); document.write( "But X-Y = 11 always.\r
\n" ); document.write( "\n" ); document.write( "X = 3 + 7T = G + 22 = T+11+22 = T+33\r
\n" ); document.write( "\n" ); document.write( "6T = 30 OR T = 5 years. and G = 5 + 11 16 years in 1748.\r
\n" ); document.write( "\n" ); document.write( "In 1750, T = 7, G = 18\r
\n" ); document.write( "\n" ); document.write( "Therefore , Sum of G and T in 1750 is 25 years\r
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