document.write( "Question 696808: Please help me with the following..Thank you!\r
\n" ); document.write( "\n" ); document.write( "Solve for x in \"a%5E2%28a-x%29=%28b%5E2%28b%2Bx%29%29-2abx\"\r
\n" ); document.write( "\n" ); document.write( "My working...where did I go wrong?
\n" ); document.write( "\"a%5E3-a%5E2x-b%5E3-b%5E2x%2B2abx=0\"
\n" ); document.write( "\"a%5E2x-b%5E2x%2B2abx=b%5E3-a%5E3=x%28a%5E2-b%5E2%2B2ab%29\"
\n" ); document.write( "\"x=%28b%5E3-a%5E3%29%2F%28a%5E2-b%5E2%2B2ab%29\"\r
\n" ); document.write( "\n" ); document.write( "The correct answer is \"x=%28a%5E2%2Bab%2Bb%5E2%29%2F%28a-b%29\"
\n" ); document.write( "

Algebra.Com's Answer #429333 by god2012(113)\"\" \"About 
You can put this solution on YOUR website!
This problem is already solved \n" ); document.write( "
\n" );