document.write( "Question 696621: divide a right angled triangle of sides ab=77 feet is the base,bc=60 feet and ca=97 feet into four equal parts longitudinally.
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #429266 by KMST(5328)\"\" \"About 
You can put this solution on YOUR website!
A triangle of sides AB=77 feet, BC=60 feet and CA=97 feet, does not have a right angle at B.
\n" ); document.write( "A triangle of sides AB=77 feet, BC=59 feet and CA=97 feet, has an angle at C that is for practical purposes a right angle (not exactly, but you would not notice the difference).
\n" ); document.write( " We need to get with
\n" ); document.write( "\"area%28AXP%29=area%28XYQP%29=area%28YZRQ%29=area%28ZBCR%29=%281%2F4%29%2Aarea%28ABC%29\"
\n" ); document.write( "
\n" ); document.write( "AXP and ABC are similar right triangles.
\n" ); document.write( "PA and CA are the corresponding longest sides of each triangle;
\n" ); document.write( "XP and BC are the corresponding shortest sides, and]=
\n" ); document.write( "AX and AB are corresponding sides too.\r
\n" ); document.write( "\n" ); document.write( "In similar triangles, the ratio of the areas equals the ratio of the lengths of the corresponding sides, squared.
\n" ); document.write( "In math equation: \"area%28ABC%29%2Farea%28AXP%29=%28AB%2FAX%29%5E2\"
\n" ); document.write( "So \"area%28AXP%29=%281%2F4%29%2Aarea%28ABC%29\" <--> \"area%28AXP%29%2Farea%28ABC%29=%281%2F4%29\" <--> \"area%28ABC%29%2Farea%28AXP%29=4\"
\n" ); document.write( "means \"%28AB%2FAX%29%5E2=4\" <--> \"AB%2FAX=sqrt%284%29=2\" or
\n" ); document.write( "\"%28AX%2FAB%29%5E2=1%2F4\" <--> \"AX%2FAB=sqrt%281%2F4%29=1%2F2\"
\n" ); document.write( "So, if AB=77 feet, \"AX=%281%2F2%29AB=%281%2F2%29%2A77\"ft --> \"AX=38.5\"ft
\n" ); document.write( "
\n" ); document.write( "If you look hard enough you will see that there are 4 \"highlight%28similar%29\" right triangles with a vertex at A:
\n" ); document.write( "ABC, AZR, AYQ, and AXP.
\n" ); document.write( "How are their areas related?
\n" ); document.write( "ABC is split into its 4 pieces of area equal to the area of AXP.
\n" ); document.write( "AYQ contains 2 of those pieces, and AZR contains 3.
\n" ); document.write( "So \"area%28AYQ%29=2%2Aarea%28AXP%29\" <--> \"area%28AYQ%29%2Farea%28AXP%29=2\"
\n" ); document.write( "and \"area%28AZR%29=3%2Aarea%28AXP%29\" <--> \"area%28AZR%29%2Farea%28AXP%29=3\"
\n" ); document.write( "Using again the fact that the ratio of areas equals the ratio of the lengths of the corresponding sides, squared,
\n" ); document.write( "\"%28AY%2FAX%29%5E2=2\" --> \"AY%2FAX=sqrt%282%29\" --> \"AY=sqrt%282%29%2AAX\" --> \"AY=38.5sqrt%282%29\" = about \"highlight%2854.4%29\" feet
\n" ); document.write( "\"%28AZ%2FAX%29%5E2=3\" --> \"AZ%2FAX=sqrt%283%29\" --> \"AZ=sqrt%283%29%2AAX\" --> \"AZ=38.5sqrt%283%29\" = about \"highlight%2866.7%29\" feet
\n" ); document.write( "
\n" );