document.write( "Question 696621: divide a right angled triangle of sides ab=77 feet is the base,bc=60 feet and ca=97 feet into four equal parts longitudinally.
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Algebra.Com's Answer #429266 by KMST(5328)![]() ![]() You can put this solution on YOUR website! A triangle of sides AB=77 feet, BC=60 feet and CA=97 feet, does not have a right angle at B. \n" ); document.write( "A triangle of sides AB=77 feet, BC=59 feet and CA=97 feet, has an angle at C that is for practical purposes a right angle (not exactly, but you would not notice the difference). \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "AXP and ABC are similar right triangles. \n" ); document.write( "PA and CA are the corresponding longest sides of each triangle; \n" ); document.write( "XP and BC are the corresponding shortest sides, and]= \n" ); document.write( "AX and AB are corresponding sides too.\r \n" ); document.write( "\n" ); document.write( "In similar triangles, the ratio of the areas equals the ratio of the lengths of the corresponding sides, squared. \n" ); document.write( "In math equation: \n" ); document.write( "So \n" ); document.write( "means \n" ); document.write( " \n" ); document.write( "So, if AB=77 feet, \n" ); document.write( " \n" ); document.write( "If you look hard enough you will see that there are 4 \n" ); document.write( "ABC, AZR, AYQ, and AXP. \n" ); document.write( "How are their areas related? \n" ); document.write( "ABC is split into its 4 pieces of area equal to the area of AXP. \n" ); document.write( "AYQ contains 2 of those pieces, and AZR contains 3. \n" ); document.write( "So \n" ); document.write( "and \n" ); document.write( "Using again the fact that the ratio of areas equals the ratio of the lengths of the corresponding sides, squared, \n" ); document.write( " \n" ); document.write( " |