document.write( "Question 696709: find range ?
\n" ); document.write( "\"sqrt%28-x%5E2%2B4x-3%29%2Bsqrt%28sin%28pi%2F2%2Asin%28pi%2F2%29%28x-1%29%29%29%29%29\"
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Algebra.Com's Answer #429258 by mouk(232)\"\" \"About 
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Let
\n" ); document.write( "\"+y+=+sqrt%28-x%5E2%2B4x-3%29+%2B+sqrt%28sin%28pi%2F2%2Asin%28pi%2F2%29%28x-1%29+%29%29+\"\r
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\n" ); document.write( "\n" ); document.write( "Then factorising the first term and tidying up the second gives:
\n" ); document.write( "\"+y+=+sqrt%28%28-x%2B1%29%28x-3%29%29+%2B+sqrt%28sin%28pi%2F2%2A%28x-1%29+%29%29+\"\r
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\n" ); document.write( "\n" ); document.write( "As we are assuming a real-valued function then both terms under the square root signs must be simultaneously positive (or zero).\r
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\n" ); document.write( "\n" ); document.write( "Firstly consider \"+%28-x%2B1%29%28x-3%29+%3E=+0+\"
\n" ); document.write( "\"+graph%28+200%2C+200%2C+-1%2C+4%2C+-10%2C+10%2C+-x%5E2%2B4x-3+%29+\"
\n" ); document.write( "The solution to this is: \"+1+%3C=+x+%3C=3+\"\r
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\n" ); document.write( "\n" ); document.write( "Secondly, consider \"+sin%28pi%2F2%2A%28x-1%29%29+%3E=+0\"
\n" ); document.write( "\"+graph%28+200%2C+200%2C+-2pi%2C+2pi%2C+-3%2C+3%2C+sin%28pi%2F2%2A%28x-1%29%29+%29+\"
\n" ); document.write( "\"+sin%28pi%2F2%2A%28x-1%29%29+%3E=+0+\"
\n" ); document.write( "\"+0%3C=+pi%2F2%2A%28x-1%29+%3C=+pi+\"
\n" ); document.write( "\"+0%3C=+x-1+%3C=+2+\"
\n" ); document.write( "\"+1%3C=+x+%3C=+3+\"\r
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\n" ); document.write( "\n" ); document.write( "So in both cases, the square root terms simultaneously exist when \"+1%3C=+x+%3C=+3+\", and this is the range.
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