document.write( "Question 696664: Solve for all values of x: (9/x)+(9/x-2)=12
\n" ); document.write( "Solve for x: 125^-2x=25^x+1
\n" ); document.write( "Please help me. For the first one I made the bottom equal and started cross multiplying it but then from there got confused cauz I couldn't simplify and my numbers were getting weird. For the second one I don't even know how to do it. We never learned it in class. Thanks in advance!
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Algebra.Com's Answer #429251 by Jolliano(16)\"\" \"About 
You can put this solution on YOUR website!
Multiply through by(x-2)(x). That gives us
\n" ); document.write( "9(x-2)(x)/(x) + 9(x-2)(x)/(x-2) = 12(x-2)(x)
\n" ); document.write( "Dividing
\n" ); document.write( "9(x-2) + 9(x) = 12(x-2)(x)
\n" ); document.write( "9x - 18 + 9x = (12x - 24)(x)
\n" ); document.write( "18x - 18 = 12x^2 - 24x
\n" ); document.write( "COLLECTING LIKE TERMS
\n" ); document.write( "-18 = 12x^2 - 24x - 18x
\n" ); document.write( "-18 = 12x^2 - 42x
\n" ); document.write( "12x^2 - 42x + 18 = 0
\n" ); document.write( "DIVIDE THROUGH BY 6
\n" ); document.write( "2x^2 - 7x + 3 = 0
\n" ); document.write( "2x^2 - 6x - x + 3 = 0
\n" ); document.write( "(2x^2 - 6x) + (-x + 3) = 0
\n" ); document.write( "2x(x - 3) -1(x - 3) = 0
\n" ); document.write( "(2x - 1)(x - 3) = 0
\n" ); document.write( "If (2x - 1) = 0
\n" ); document.write( "2x = 1
\n" ); document.write( "x = 0.5
\n" ); document.write( "If (x - 3) = 0
\n" ); document.write( "x = 3
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