document.write( "Question 696664: Solve for all values of x: (9/x)+(9/x-2)=12
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document.write( "Solve for x: 125^-2x=25^x+1
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document.write( "Please help me. For the first one I made the bottom equal and started cross multiplying it but then from there got confused cauz I couldn't simplify and my numbers were getting weird. For the second one I don't even know how to do it. We never learned it in class. Thanks in advance! \n" );
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Algebra.Com's Answer #429251 by Jolliano(16) You can put this solution on YOUR website! Multiply through by(x-2)(x). That gives us \n" ); document.write( "9(x-2)(x)/(x) + 9(x-2)(x)/(x-2) = 12(x-2)(x) \n" ); document.write( "Dividing \n" ); document.write( "9(x-2) + 9(x) = 12(x-2)(x) \n" ); document.write( "9x - 18 + 9x = (12x - 24)(x) \n" ); document.write( "18x - 18 = 12x^2 - 24x \n" ); document.write( "COLLECTING LIKE TERMS \n" ); document.write( "-18 = 12x^2 - 24x - 18x \n" ); document.write( "-18 = 12x^2 - 42x \n" ); document.write( "12x^2 - 42x + 18 = 0 \n" ); document.write( "DIVIDE THROUGH BY 6 \n" ); document.write( "2x^2 - 7x + 3 = 0 \n" ); document.write( "2x^2 - 6x - x + 3 = 0 \n" ); document.write( "(2x^2 - 6x) + (-x + 3) = 0 \n" ); document.write( "2x(x - 3) -1(x - 3) = 0 \n" ); document.write( "(2x - 1)(x - 3) = 0 \n" ); document.write( "If (2x - 1) = 0 \n" ); document.write( "2x = 1 \n" ); document.write( "x = 0.5 \n" ); document.write( "If (x - 3) = 0 \n" ); document.write( "x = 3 \n" ); document.write( " |