document.write( "Question 696671: 1. Find the equation of a line that is parallel to y= 2x-3 had has a y-intercept of 4\r
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\n" ); document.write( "\n" ); document.write( "2. Find the equation of a line that is perpendicular y=-3x + 7 and has a y-intercept of -2\r
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\n" ); document.write( "\n" ); document.write( "3. Find the equation of a line that is parallel to y =2x -1 and goes through the point(6,2)\r
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\n" ); document.write( "\n" ); document.write( "4.Find the equation of a line that is perpendicular to y=1/3x + 2 and goes through the point (1,7)
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Algebra.Com's Answer #429234 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "1. Find the equation of a line that is parallel to \"y=+2x-3\" had has a y-intercept of \"4\" (means it passes through point (\"0\",\"4\"))\r
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Solved by pluggable solver: Finding the Equation of a Line Parallel or Perpendicular to a Given Line

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\n" ); document.write( " Since any two parallel lines have the same slope we know the slope of the unknown line is \"2\" (its from the slope of \"y=2%2Ax-3\" which is also \"2\").\n" ); document.write( "Also since the unknown line goes through (0,4), we can find the equation by plugging in this info into the point-slope formula
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\n" ); document.write( " Point-Slope Formula:
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\n" ); document.write( " \"y-y%5B1%5D=m%28x-x%5B1%5D%29\" where m is the slope and (\"x%5B1%5D\",\"y%5B1%5D\") is the given point
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\n" ); document.write( " \"y-4=2%2A%28x-0%29\" Plug in \"m=2\", \"x%5B1%5D=0\", and \"y%5B1%5D=4\"
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\n" ); document.write( " \"y-4=2%2Ax-%282%29%280%29\" Distribute \"2\"
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\n" ); document.write( " \"y-4=2%2Ax-0\" Multiply
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\n" ); document.write( " \"y=2%2Ax-0%2B4\"Add \"4\" to both sides to isolate y
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\n" ); document.write( " \"y=2%2Ax%2B4\" Combine like terms
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\n" ); document.write( " So the equation of the line that is parallel to \"y=2%2Ax-3\" and goes through (\"0\",\"4\") is \"y=2%2Ax%2B4\"
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\n" ); document.write( " So here are the graphs of the equations \"y=2%2Ax-3\" and \"y=2%2Ax%2B4\"
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\n" ); document.write( " graph of the given equation \"y=2%2Ax-3\" (red) and graph of the line \"y=2%2Ax%2B4\"(green) that is parallel to the given graph and goes through (\"0\",\"4\")
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\n" ); document.write( "\n" ); document.write( "2. Find the equation of a line that is perpendicular \"y=-3x+%2B+7\" and has a y-intercept of \"-2\" (means it passes through point (\"0\",\"-2\"))\r
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Solved by pluggable solver: Finding the Equation of a Line Parallel or Perpendicular to a Given Line

\n" ); document.write( "
\n" ); document.write( " Since any two parallel lines have the same slope we know the slope of the unknown line is \"-3\" (its from the slope of \"y=-3%2Ax%2B7\" which is also \"-3\").\n" ); document.write( "Also since the unknown line goes through (0,-2), we can find the equation by plugging in this info into the point-slope formula
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\n" ); document.write( " Point-Slope Formula:
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\n" ); document.write( " \"y-y%5B1%5D=m%28x-x%5B1%5D%29\" where m is the slope and (\"x%5B1%5D\",\"y%5B1%5D\") is the given point
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\n" ); document.write( " \"y%2B2=-3%2A%28x-0%29\" Plug in \"m=-3\", \"x%5B1%5D=0\", and \"y%5B1%5D=-2\"
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\n" ); document.write( " \"y%2B2=-3%2Ax%2B%283%29%280%29\" Distribute \"-3\"
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\n" ); document.write( " \"y%2B2=-3%2Ax-0\" Multiply
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\n" ); document.write( " \"y=-3%2Ax-0-2\"Subtract \"-2\" from both sides to isolate y
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\n" ); document.write( " \"y=-3%2Ax-2\" Combine like terms
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\n" ); document.write( " So the equation of the line that is parallel to \"y=-3%2Ax%2B7\" and goes through (\"0\",\"-2\") is \"y=-3%2Ax-2\"
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\n" ); document.write( " So here are the graphs of the equations \"y=-3%2Ax%2B7\" and \"y=-3%2Ax-2\"
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\n" ); document.write( "
\n" ); document.write( " graph of the given equation \"y=-3%2Ax%2B7\" (red) and graph of the line \"y=-3%2Ax-2\"(green) that is parallel to the given graph and goes through (\"0\",\"-2\")
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\n" ); document.write( "\n" ); document.write( "3. Find the equation of a line that is parallel to \"y+=2x+-1\" and goes through the point (\"6\",\"2\"))\r
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Solved by pluggable solver: Finding the Equation of a Line Parallel or Perpendicular to a Given Line

\n" ); document.write( "
\n" ); document.write( " Since any two parallel lines have the same slope we know the slope of the unknown line is \"2\" (its from the slope of \"y=2%2Ax-1\" which is also \"2\").\n" ); document.write( "Also since the unknown line goes through (6,2), we can find the equation by plugging in this info into the point-slope formula
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\n" ); document.write( " Point-Slope Formula:
\n" ); document.write( "
\n" ); document.write( " \"y-y%5B1%5D=m%28x-x%5B1%5D%29\" where m is the slope and (\"x%5B1%5D\",\"y%5B1%5D\") is the given point
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\n" ); document.write( " \"y-2=2%2A%28x-6%29\" Plug in \"m=2\", \"x%5B1%5D=6\", and \"y%5B1%5D=2\"
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\n" ); document.write( " \"y-2=2%2Ax-%282%29%286%29\" Distribute \"2\"
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\n" ); document.write( " \"y-2=2%2Ax-12\" Multiply
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\n" ); document.write( " \"y=2%2Ax-12%2B2\"Add \"2\" to both sides to isolate y
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\n" ); document.write( " \"y=2%2Ax-10\" Combine like terms
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\n" ); document.write( " So the equation of the line that is parallel to \"y=2%2Ax-1\" and goes through (\"6\",\"2\") is \"y=2%2Ax-10\"
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\n" ); document.write( " So here are the graphs of the equations \"y=2%2Ax-1\" and \"y=2%2Ax-10\"
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\n" ); document.write( "
\n" ); document.write( " graph of the given equation \"y=2%2Ax-1\" (red) and graph of the line \"y=2%2Ax-10\"(green) that is parallel to the given graph and goes through (\"6\",\"2\")
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\n" ); document.write( "\n" ); document.write( "4.Find the equation of a line that is perpendicular to \"y=%281%2F3%29x+%2B+2\" and goes through the point (\"1\",\"7\"))\r
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Solved by pluggable solver: Finding the Equation of a Line Parallel or Perpendicular to a Given Line

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\n" ); document.write( " Since any two parallel lines have the same slope we know the slope of the unknown line is \"1%2F3\" (its from the slope of \"y=%281%2F3%29%2Ax%2B2\" which is also \"1%2F3\").\n" ); document.write( "Also since the unknown line goes through (1,7), we can find the equation by plugging in this info into the point-slope formula
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\n" ); document.write( " Point-Slope Formula:
\n" ); document.write( "
\n" ); document.write( " \"y-y%5B1%5D=m%28x-x%5B1%5D%29\" where m is the slope and (\"x%5B1%5D\",\"y%5B1%5D\") is the given point
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\n" ); document.write( " \"y-7=%281%2F3%29%2A%28x-1%29\" Plug in \"m=1%2F3\", \"x%5B1%5D=1\", and \"y%5B1%5D=7\"
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\n" ); document.write( " \"y-7=%281%2F3%29%2Ax-%281%2F3%29%281%29\" Distribute \"1%2F3\"
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\n" ); document.write( " \"y-7=%281%2F3%29%2Ax-1%2F3\" Multiply
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\n" ); document.write( " \"y=%281%2F3%29%2Ax-1%2F3%2B7\"Add \"7\" to both sides to isolate y
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\n" ); document.write( " \"y=%281%2F3%29%2Ax-1%2F3%2B21%2F3\" Make into equivalent fractions with equal denominators
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\n" ); document.write( " \"y=%281%2F3%29%2Ax%2B20%2F3\" Combine the fractions
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\n" ); document.write( " \"y=%281%2F3%29%2Ax%2B20%2F3\" Reduce any fractions
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\n" ); document.write( " So the equation of the line that is parallel to \"y=%281%2F3%29%2Ax%2B2\" and goes through (\"1\",\"7\") is \"y=%281%2F3%29%2Ax%2B20%2F3\"
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\n" ); document.write( " So here are the graphs of the equations \"y=%281%2F3%29%2Ax%2B2\" and \"y=%281%2F3%29%2Ax%2B20%2F3\"
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\n" ); document.write( "
\n" ); document.write( " graph of the given equation \"y=%281%2F3%29%2Ax%2B2\" (red) and graph of the line \"y=%281%2F3%29%2Ax%2B20%2F3\"(green) that is parallel to the given graph and goes through (\"1\",\"7\")
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