document.write( "Question 696370:
\n" ); document.write( "when a plane flies into the wind it can travel 3000 km in 6 hours. when it flies with the wind, it goes the same distance in 5 hours. find the rate of the plane in still air.
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Algebra.Com's Answer #429166 by checkley79(3341)\"\" \"About 
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D=RT
\n" ); document.write( "3000=(R)6 RATE AGAINST THE WIND.
\n" ); document.write( "R=3000/6
\n" ); document.write( "R=500 KPH.
\n" ); document.write( "3000=(R)5 RATE WITH THE WIND.
\n" ); document.write( "R=3000/5
\n" ); document.write( "R=600 KPH.
\n" ); document.write( "(600-500)/2
\n" ); document.write( "100/2=50 KPH. IS THE SPEED OF THE WIND.
\n" ); document.write( "500-50=450 ANS. FOR THE SPPD OF THE PLANE IN STILL AIR
\n" ); document.write( "400+50=450 DITTO.
\n" ); document.write( "PROOF:
\n" ); document.write( "3000=500*6
\n" ); document.write( "3000=3000
\n" ); document.write( "3000=600*5
\n" ); document.write( "3000=3000\r
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