document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=4722>Question 4722</A>: <I><SPAN STYLE=\"word-break: break-all;\"> What is the sum of the digits of the four-digit numbers formed using the digits <BR>\n" );
document.write( "2,4,6,8(repetitions not allowed). </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #429066 by </B><A HREF=/tutors/aboutme.mpl?userid=trip.3c><B>trip.3c(1)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=trip.3c><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=429066\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Total no of arrangements possible = 4! = 24<BR>\n" );
document.write( "So, no of occurences for all the 4 digits unit place = 24/4 = 6times. So sum of all such unit numbers = 6 [ 8 + 6 + 4 + 2 ] = 6*20 = 120<BR>\n" );
document.write( "Similarly, for tenth, hundredth and thousandth place<BR>\n" );
document.write( "The sum of 24 times 120 in 4 places(thousandth, hundredth, tenth and unit) = 133320 </SPAN>\n" );
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