document.write( "Question 696362: Please answer my question: If 6 kilos of oranges and 5 kilos of apples cost 419 while 5 kilos of oranges and 7 kilos of apples cost 488, what is the cost of each per kilo? \n" ); document.write( "

Algebra.Com's Answer #429043 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

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If 6 kilos of oranges and 5 kilos of apples cost 419 while 5 kilos of oranges
\n" ); document.write( " and 7 kilos of apples cost 488, what is the cost of each per kilo?
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\n" ); document.write( "Let x = cost of oranges per kilo
\n" ); document.write( "Let y = cost of apples
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\n" ); document.write( "write an equation for each transaction
\n" ); document.write( "6x + 5y = 419
\n" ); document.write( "5x + 7y = 488
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\n" ); document.write( "Use elimination here, mult the 1st eq by 7 and the 2nd eq by 5
\n" ); document.write( "42x + 35y = 2933
\n" ); document.write( "25x + 35y = 2440
\n" ); document.write( "-------------------subtraction eliminates y, find x
\n" ); document.write( "17x = 493
\n" ); document.write( "x = 493/17
\n" ); document.write( "x = 29 is the cost of the oranges
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\n" ); document.write( "You can find the cost of the apples, substitute 29 for x in one of the equations and find y.
\n" ); document.write( "Check your solutions in the other equation.
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