document.write( "Question 696359: Steve is two thirds as old as Alex. In seven years, Steve will be three fourths as old as Alex. How old are they now? \n" ); document.write( "
Algebra.Com's Answer #429021 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Steve is two thirds as old as Alex. \n" ); document.write( " In seven years, Steve will be three fourths as old as Alex. \n" ); document.write( " How old are they now? \n" ); document.write( ": \n" ); document.write( "let s = Steve's present age \n" ); document.write( "Let a = Alex's age \n" ); document.write( ": \n" ); document.write( "Write an equation for each statement \n" ); document.write( ": \n" ); document.write( "\"Steve is two thirds as old as Alex.\" \n" ); document.write( "s = \n" ); document.write( "get rid of the fraction, mult both side by 3 \n" ); document.write( "3s = 2a \n" ); document.write( "3s - 2a = 0 \n" ); document.write( ": \n" ); document.write( "\" In seven years, Steve will be three fourths as old as Alex.\" \n" ); document.write( "s + 7 = \n" ); document.write( "mult both sides by 4 \n" ); document.write( "4(s+7) = 3(a + 7) \n" ); document.write( "4s + 28 = 3a + 21 \n" ); document.write( "4s - 3a = 21 - 28 \n" ); document.write( "4s - 3a = -7 \n" ); document.write( ": \n" ); document.write( "Use elimination here, mult the 1st equation by 3, the 2nd equation by 2 \n" ); document.write( "9s - 6s = 0 \n" ); document.write( "8s - 6a = -14 \n" ); document.write( "---------------subtraction eliminates a, find s \n" ); document.write( "s = 14 yrs is Steve's age \n" ); document.write( "then \n" ); document.write( "3(14) - 2(a) = 0 \n" ); document.write( "42 - 2a = 0 \n" ); document.write( "-2a = -42 \n" ); document.write( "a = 21 yrs is Alex's age \n" ); document.write( "; \n" ); document.write( ": \n" ); document.write( "Confirm this in the statement: \n" ); document.write( "\"In seven years, Steve will be three fourths as old as Alex.\" \n" ); document.write( "14 + 7 = \n" ); document.write( "21 = |