document.write( "Question 696359: Steve is two thirds as old as Alex. In seven years, Steve will be three fourths as old as Alex. How old are they now? \n" ); document.write( "
Algebra.Com's Answer #429021 by ankor@dixie-net.com(22740)\"\" \"About 
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Steve is two thirds as old as Alex.
\n" ); document.write( " In seven years, Steve will be three fourths as old as Alex.
\n" ); document.write( " How old are they now?
\n" ); document.write( ":
\n" ); document.write( "let s = Steve's present age
\n" ); document.write( "Let a = Alex's age
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\n" ); document.write( "Write an equation for each statement
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\n" ); document.write( "\"Steve is two thirds as old as Alex.\"
\n" ); document.write( "s = \"2%2F3\"a
\n" ); document.write( "get rid of the fraction, mult both side by 3
\n" ); document.write( "3s = 2a
\n" ); document.write( "3s - 2a = 0
\n" ); document.write( ":
\n" ); document.write( "\" In seven years, Steve will be three fourths as old as Alex.\"
\n" ); document.write( "s + 7 = \"3%2F4\"(a+7)
\n" ); document.write( "mult both sides by 4
\n" ); document.write( "4(s+7) = 3(a + 7)
\n" ); document.write( "4s + 28 = 3a + 21
\n" ); document.write( "4s - 3a = 21 - 28
\n" ); document.write( "4s - 3a = -7
\n" ); document.write( ":
\n" ); document.write( "Use elimination here, mult the 1st equation by 3, the 2nd equation by 2
\n" ); document.write( "9s - 6s = 0
\n" ); document.write( "8s - 6a = -14
\n" ); document.write( "---------------subtraction eliminates a, find s
\n" ); document.write( "s = 14 yrs is Steve's age
\n" ); document.write( "then
\n" ); document.write( "3(14) - 2(a) = 0
\n" ); document.write( "42 - 2a = 0
\n" ); document.write( "-2a = -42
\n" ); document.write( "a = 21 yrs is Alex's age
\n" ); document.write( ";
\n" ); document.write( ":
\n" ); document.write( "Confirm this in the statement:
\n" ); document.write( "\"In seven years, Steve will be three fourths as old as Alex.\"
\n" ); document.write( "14 + 7 = \"3%2F4\"(21+7)
\n" ); document.write( "21 = \"3%2F4\"(28)
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