document.write( "Question 62148: Hope you can help me:
\n" ); document.write( "Solve sin2y = cos4y for y, where 0 <= y < 360
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Algebra.Com's Answer #42902 by joyofmath(189)\"\" \"About 
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Solve sin2y = cos4y for y, where 0 <= y < 360\r
\n" ); document.write( "\n" ); document.write( "Let x = 2y. Then, \"sinx+=+cos2x\".
\n" ); document.write( "There's a trig identity: \"cos2x+=+1-2%28sinx%29%5E2\"\r
\n" ); document.write( "\n" ); document.write( "We use that identity and get: \"sin%28x%29+=+1-2%28sinx%29%5E2\"\r
\n" ); document.write( "\n" ); document.write( "Let some variable, say g, = sinx.\r
\n" ); document.write( "\n" ); document.write( "Then, \"g+=+1-2g%5E2\".
\n" ); document.write( "Or, \"2g%5E2%2Bg+=+1\"
\n" ); document.write( "Or, \"2g%5E2%2Bg-1+=+0\".
\n" ); document.write( "This factors into \"%282g-1%29%28g%2B1%29+=+0\".
\n" ); document.write( "So, \"g=1%2F2\" or \"g=-1\".\r
\n" ); document.write( "\n" ); document.write( "So, since \"g+=+sinx\", \"sinx+=+1%2F2\" or \"sinx+=+-1\".\r
\n" ); document.write( "\n" ); document.write( "Since x = 2y, \"sin%282y%29+=+1%2F2\" or \"sin%282y%29+=+-1\".
\n" ); document.write( "So, 2y = 270 degress or 2y = 30 degrees.
\n" ); document.write( "So, the answer is y = 135 degrees or y = 15 degrees.\r
\n" ); document.write( "\n" ); document.write( "Let's verify the answer:\r
\n" ); document.write( "\n" ); document.write( "sin(2*135) = sin(270) = -1 and cos(4*135) = cos(540) = cos(180) = -1.
\n" ); document.write( "sin(2*15) = sin(30) = 1/2 and cos(60) = 1/2.
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