document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=62147>Question 62147</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Joseph has 4 times as many quarters as he does dimes. If he has a total of  $2.65, how many of each type of coin does he have? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #42899 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=42899\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Joseph has 4 times as many quarters as he does dimes. If he has a total of $2.65, how many of each type of coin does he have?<BR>\n" );
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document.write( "Let the number of dimes be \"x\"; Value of these is 10x cents<BR>\n" );
document.write( "The number of quarters is \"4x\"; Value of these is 25(4x)=100x cents<BR>\n" );
document.write( "EQUATION:<BR>\n" );
document.write( "value + value = 265 cets<BR>\n" );
document.write( "10x+100x=265<BR>\n" );
document.write( "110x=265<BR>\n" );
document.write( "x=2.4...<BR>\n" );
document.write( "This is not possible as \"x\" is a count of coins.<BR>\n" );
document.write( "Check your problem data and your posting.<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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