document.write( "Question 696364: A father and his son can do a job in 20 days. The father can do four times as much work as his son in a given amount of time. In how many days can the father do the job alone? \n" ); document.write( "
Algebra.Com's Answer #428983 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! A father and his son can do a job in 20 days. \n" ); document.write( " The father can do four times as much work as his son in a given amount of time. \n" ); document.write( " In how many days can the father do the job alone? \n" ); document.write( ": \n" ); document.write( "let d = time required by Dad working alone \n" ); document.write( "then \n" ); document.write( "4d = time required by sonny \n" ); document.write( ": \n" ); document.write( "let the completed job = 1 \n" ); document.write( ": \n" ); document.write( "Each will do a fraction of the job, the two fractions add up to one. \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( "multiply by 4d \n" ); document.write( "4(20) + 20 = 4d \n" ); document.write( "100 = 4d \n" ); document.write( "d = 100/4 \n" ); document.write( "d = 25 days dad alone \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check this, son's time 4(25) \n" ); document.write( " \n" ); document.write( ".8 + .2 = 1 \n" ); document.write( " |