document.write( "Question 696354: $\"+f%28x%29=+sqrt%28x%2B5%29+%2B3+\"$ . How do I find the domain and range without a calculator? \n" ); document.write( "

Algebra.Com's Answer #428966 by mouk(232) $\"\"$ $\"About$

You can put this solution on YOUR website!
You cannot take the square root of a -ve number, so $\"+x%2B5+%3E=+0+\"$
\n" ); document.write( "Hence, $\"+x+%3E=+-5+\"$ \r
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\n" ); document.write( "\n" ); document.write( "So the range is $\"+x+%3E=+-5+\"$ \r
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\n" ); document.write( "\n" ); document.write( " $\"+sqrt%28x%2B5%29+\"$ is smallest when $\"+x%2B5+=+0+\"$ , ie $\"+x=-5+\"$ , for all other values of x (subject to $\"+x+%3E=+-5+\"$ ) then
\n" ); document.write( " $\"+x%2B5+%3E+0+\"$ so $\"+sqrt%28x%2B5%29%3E0+\"$ \r
\n" ); document.write( "\n" ); document.write( "so then $\"+sqrt%28x%2B5%29%2B3+\"$ has a minimum values of 3 when $\"+x=-5+\"$ \r
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\n" ); document.write( "\n" ); document.write( "so the domain is $\"+f%28x%29+%3E=3+\"$ or if you prefer $\"+3+%3C=+f%28x%29+%3C=+infinity+\"$ \n" ); document.write( "

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