document.write( "Question 696356: Two men are driving. One is travelling 70 mph, and the other is travelling 98 mph. The faster one is 14 miles behind the one that is going 70 mph. How long will it take the faster one (98mph) to catch up to the slower one (70mph)?\r
\n" ); document.write( "\n" ); document.write( "--I tried the problem already and I got 1/2 an hour. I'm unsure though because I'm very uneasy with word problems. Thanks!
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Algebra.Com's Answer #428959 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
Try it this way:
\n" ); document.write( "Start a stopwatch when the faster one is
\n" ); document.write( "exactly 14 miles behind the slower one.
\n" ); document.write( "You will hit the stopwatch when the
\n" ); document.write( "faster one has caught the slower one.
\n" ); document.write( "Call the time on the stopwatch \"+t+\" ( in hours )
\n" ); document.write( "----------------------------------------
\n" ); document.write( "Let \"+d+\" = distance in miles that the slower one
\n" ); document.write( "travels until he is caught.
\n" ); document.write( "----------------------
\n" ); document.write( "Equation for slower one:
\n" ); document.write( "(1) \"+d+=+70t+\"
\n" ); document.write( "Equation for faster one:
\n" ); document.write( "(2) \"+d+%2B+14+=+98t+\"
\n" ); document.write( "------------------
\n" ); document.write( "Substitute (1) into (2)
\n" ); document.write( "(2) \"+70t+%2B+14+=+98t+\"
\n" ); document.write( "(2) \"+28t+=+14+\"
\n" ); document.write( "(2) \"+t+=+.5+\"
\n" ); document.write( "The faster one catches the slower one
\n" ); document.write( "in a half hour.
\n" ); document.write( "Looks like you did it right.\r
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