document.write( "Question 696337: Write the following in standard form and name the conic section.
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document.write( "1. x^2+6x-3y+15=0
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document.write( "2. x^2+y^2-2x+2y-7=0
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document.write( "and
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document.write( "3. x^2-6x+9+y^2-18y+81=36
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document.write( "I know you have to set all equations equal to zero, and complete the square i just dont know how and what order. PLEASE HELP! \n" );
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Algebra.Com's Answer #428950 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Write the following in standard form and name the conic section. \n" ); document.write( "1. x^2+6x-3y+15=0 \n" ); document.write( "x^2+6x +9 = 3y-15 + 9 \n" ); document.write( "(x+3)^2 = 3y-6 \n" ); document.write( "3(y-2) = (x+3)^2 \n" ); document.write( "y = (1/3)(x^3)^2+2 \n" ); document.write( "---- \n" ); document.write( "Parabola opening upward from (-3,2) \n" ); document.write( "==========================================\r \n" ); document.write( "\n" ); document.write( "2. x^2+y^2-2x+2y-7=0 \n" ); document.write( "(x^2-2x+1) + (y^2+2y+1) = 7 + 1 + 1 \n" ); document.write( "(x-1)^2 + (y+1)^2 = 9 \n" ); document.write( "Circle with center at (1,-1) and radius = 3 \n" ); document.write( "=========================================== \n" ); document.write( "and \n" ); document.write( "3. x^2-6x+9+y^2-18y+81=36 \n" ); document.write( "x^2-6x+9 + y^2-18y+81 = 36 \n" ); document.write( "(x-3)^2 + (y-9)^2 = 36 \n" ); document.write( "Circle with center at (3,9) and radius = 6 \n" ); document.write( "============================================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |