document.write( "Question 62098: 2 trains left the same city at the same time, traveling in opposite directions. the eastbound train traveles for 10 hours, and the westbound train traveles for 5 hours. They are now 1300 km. apart. the westbound train's rate is 20 km/h faster than the eastbound train. Find the rate of the speed of each train. \n" ); document.write( "
Algebra.Com's Answer #42891 by ankor@dixie-net.com(22740)\"\" \"About 
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2 trains left the same city at the same time, traveling in opposite directions. the eastbound train travels for 10 hours, and the westbound train travels for 5 hours. They are now 1300 km. apart. the westbound train's rate is 20 km/h faster than the eastbound train. Find the rate of the speed of each train.
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\n" ); document.write( "Let s = speed of the slower train:
\n" ); document.write( "Then (s+20) = speed of the faster train
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\n" ); document.write( "Dist = time * speed
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\n" ); document.write( "Eastbound dist + westbound dist = 1300
\n" ); document.write( "10s + 5(s+20) = 1300
\n" ); document.write( "10s + 5s + 100 = 1300
\n" ); document.write( "15s = 1300 - 100
\n" ); document.write( "15s = 1200
\n" ); document.write( "s = 1200/15
\n" ); document.write( "s = 80 mph for slow one and 100 mph for the fast one
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\n" ); document.write( "Check 80*10 + 100*5 = 1300
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\n" ); document.write( "How about this? Did it make sense to you?
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