document.write( "Question 62124: What is the capacity of a silo that is 30ft in height, the face against the barn is 10ft wide, and the barn is 5 ft. from the center of the circle? \n" ); document.write( "
Algebra.Com's Answer #42888 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
The intersection of the barn and silo is a secant line
\n" ); document.write( "that cuts across the circular base and is 10' long.
\n" ); document.write( "Draw a perpendicular from center of silo to the center of the secant.
\n" ); document.write( "Problem says center to the secant is 5\". It divides the secant into
\n" ); document.write( "2 5' sections, forming 2 45-45-90 triangles. The area of the
\n" ); document.write( "base of the silo is therefore,
\n" ); document.write( "\"pi%2A%285%29%5E2+-+%28pi%2A%285%5E2%29%2F4+-+%281%2F2%29%2A%285sqrt%282%29%29%5E2%29\"
\n" ); document.write( "\"25pi+-+%28%2825%2F4%29%2Api+-+50%2F2%29\"
\n" ); document.write( "\"25%28pi+-+pi%2F4+%2B+1%29\"
\n" ); document.write( "\"25%283pi%2F4+%2B+1%29\"
\n" ); document.write( "capacity is height X area of base
\n" ); document.write( "\"30%2A25%2A%283.3562%29\"
\n" ); document.write( "\"1767\" ft3
\n" ); document.write( "unless I made a mistake
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