document.write( "Question 696240: The length of a rectangle is 4 in. more than its width. If 2 in. are taken from the length and added to the width, the figure becomes a square with an area of 192 in.^2. What are the dimensions of the original figure? \n" ); document.write( "

Algebra.Com's Answer #428873 by solver91311(24713) $\"\"$ $\"About$

You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "The square root of 192 is

, so the original length must have been

and the width

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\n" ); document.write( "\n" ); document.write( "John
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\n" ); document.write( "Egw to Beta kai to Sigma
\n" ); document.write( "My calculator said it, I believe it, that settles it
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