document.write( "Question 62096: The length of a rectangle is 4 cm less than 3 times its width. If the lenght is increased by 8 cm and the width is decreased by 2 cm, the perimeter will be 100 cm. Find the dimensions of the original rectangle. \n" ); document.write( "
Algebra.Com's Answer #42887 by joyofmath(189)\"\" \"About 
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The length of a rectangle is 4 cm less than 3 times its width. If the lenght is increased by 8 cm and the width is decreased by 2 cm, the perimeter will be 100 cm. Find the dimensions of the original rectangle.\r
\n" ); document.write( "\n" ); document.write( "Let W be the width of the original rectangle.
\n" ); document.write( "Let L be the length of the original rectangle. Then, \"L=3W-4\".\r
\n" ); document.write( "\n" ); document.write( "If the perimeter becomes 100 when L is increased by 8 and when W is decreased by 2 then:\r
\n" ); document.write( "\n" ); document.write( "Old perimeter = \"2%28W%2BL%29\".
\n" ); document.write( "New perimeter = \"2%28W-2%2BL%2B8%29+=+100\".\r
\n" ); document.write( "\n" ); document.write( "We use the fact that \"L=3W-4\" to replace L in the new perimeter equation with \"W-2\". \r
\n" ); document.write( "\n" ); document.write( "So, \"2%28W-2%2B%283W-4%29%2B8%29+=+100\".
\n" ); document.write( "Or, \"2%28W-2%2B3W-4%2B8%29+=+100\".
\n" ); document.write( "Or, \"2W-4%2B6W-8%2B16+=+100\".
\n" ); document.write( "Or, \"8W%2B4+=+100\".
\n" ); document.write( "Or, \"8W+=+96\".
\n" ); document.write( "So, \"W=12\".
\n" ); document.write( "\"L=3W-4+=+3%2812%29-4+=+32\".
\n" ); document.write( "So, \"L=32\".\r
\n" ); document.write( "\n" ); document.write( "Verify:
\n" ); document.write( "If L is increased by 8 and W is decreased by 2 then \"L=40\" and \"W=10\". So, the perimeter is \"2%2AL%2AW+=+100\".
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