document.write( "Question 696115: A 5% salt solution is mixed with a 10% salt solution. How many milliliters of each solution are needed to obtain 400 milliliters of an 8% solution. \r
\n" ); document.write( "\n" ); document.write( "s= number of milliliters of 5% salt solution
\n" ); document.write( "t= number of milliliters of 10% s alt solution
\n" ); document.write( "I wrote an equation of
\n" ); document.write( "(s+t=400
\n" ); document.write( "(.05s+.1t=40
\n" ); document.write( "i tried solving but got stuck. am i on the right track?
\n" ); document.write( "

Algebra.Com's Answer #428807 by MathTherapy(10552)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "A 5% salt solution is mixed with a 10% salt solution. How many milliliters of each solution are needed to obtain 400 milliliters of an 8% solution. \r
\n" ); document.write( "\n" ); document.write( "s= number of milliliters of 5% salt solution
\n" ); document.write( "t= number of milliliters of 10% s alt solution
\n" ); document.write( "I wrote an equation of
\n" ); document.write( "(s+t=400
\n" ); document.write( "(.05s+.1t=40
\n" ); document.write( "i tried solving but got stuck. am i on the right track?\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Let amount of 5% salt solution to be mixed be F
\n" ); document.write( "Then amount of 10% salt solution to be mixed = 400 – F
\n" ); document.write( "Therefore, .05F + .1(400 – F) = .08(F + 400 – F)
\n" ); document.write( ".05F + 40 - .1F = 32
\n" ); document.write( ".05F - .1F = 32 – 40
\n" ); document.write( "- .05F = - 8
\n" ); document.write( "F, or amount of 5% salt solution to be mixed = \"%28-+8%29%2F-+.05\", or \"highlight_green%28160%29\" mL\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Amount of 10% salt solution to be mixed = 400 – 160, or \"highlight_green%28240%29\" mL\r
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\n" ); document.write( "\n" ); document.write( "OR\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Doing it your way:
\n" ); document.write( "s + t = 400
\n" ); document.write( ".05s + .1t = .08(400) ---- .05s + .1t = 32\r
\n" ); document.write( "\n" ); document.write( "You can now solve for s and then t, or vice-versa\r
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\n" ); document.write( "\n" ); document.write( "If you notice, you'll see that you're on the right track, with the exception that the 2nd equation should be .05s + .1t = 32, instead of .05s + .1t = 40\r
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\n" ); document.write( "\n" ); document.write( "You can do the check!!\r
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\n" ); document.write( "\n" ); document.write( "Send comments and “thank-yous” to “D” at MathMadEzy@aol.com
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