document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=696102>Question 696102</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In equilateral triangle DEF, measure of angle D=3x+y, measure of angle E= 2x+40, and measure of angle F= 2y. find x,y, measure of angle D and measure of angle F.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #428796 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=428796\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> In equilateral triangle DEF, measure of angle D=3x+y, measure of angle E= 2x+40, and measure of angle F= 2y. find x,y, measure of angle D and measure of angle F. <BR>\n" );
document.write( "------<BR>\n" );
document.write( "D = E<BR>\n" );
document.write( "3x+y = 2x+40<BR>\n" );
document.write( "y = -x+40<BR>\n" );
document.write( "-------------------<BR>\n" );
document.write( "D = F<BR>\n" );
document.write( "3x+y = 2y<BR>\n" );
document.write( "y = 3x<BR>\n" );
document.write( "----<BR>\n" );
document.write( "Therefore: 3x = -x+40<BR>\n" );
document.write( "4x = 40<BR>\n" );
document.write( "x = 10<BR>\n" );
document.write( "---<BR>\n" );
document.write( "y = -x+40<BR>\n" );
document.write( "y = -10+40<BR>\n" );
document.write( "y = 30<BR>\n" );
document.write( "------<BR>\n" );
document.write( "D = 3x+y = 3*10 + 30 = 60<BR>\n" );
document.write( "D = E = F = 60 degrees<BR>\n" );
document.write( "===========================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );