document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=696040>Question 696040</A>: <I><SPAN STYLE=\"word-break: break-all;\"> For a line of slope -3/4 thru (2, -5), find y when x= -3<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #428789 by </B><A HREF=/tutors/aboutme.mpl?userid=rfer><B>rfer(16322)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rfer><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=428789\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> y=mx+b<BR>\n" );
document.write( "-5=-3/4*2+b<BR>\n" );
document.write( "-5=-1.5+b<BR>\n" );
document.write( "-3.5=b<BR>\n" );
document.write( "------------------<BR>\n" );
document.write( "y=-3/4*-3-3.5<BR>\n" );
document.write( "y=2.25-3.5<BR>\n" );
document.write( "y=-1.25 </SPAN>\n" );
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