document.write( "Question 695774:
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document.write( "On Monday, Roger drove to work in 38 minutes. On Tuesday, he averaged 10 miles per hour more, and it took him 5 minutes less to get to work. How far (in miles) does he travel to work? \n" );
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Algebra.Com's Answer #428774 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! On Monday, Roger drove to work in 38 minutes. \n" ); document.write( " On Tuesday, he averaged 10 miles per hour more, and it took him 5 minutes less to get to work. \n" ); document.write( " How far (in miles) does he travel to work? \n" ); document.write( ": \n" ); document.write( "Find his speed first \n" ); document.write( ": \n" ); document.write( "The dist is the same each day, write a distance equation dist = time * speed \n" ); document.write( "we have to change the minutes to hours \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( "multiply both sides by 60 \n" ); document.write( "38s = 33(s + 10) \n" ); document.write( "38s - 33s = 330 \n" ); document.write( "5s = 330 \n" ); document.write( "s = 330/5 \n" ); document.write( "s = 66 mph on Monday \n" ); document.write( "and \n" ); document.write( "76 mph on Tuesday \n" ); document.write( ": \n" ); document.write( "Find the distance \n" ); document.write( " \n" ); document.write( "check that the distance is the same on Tuesday \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |