document.write( "Question 695850: Let E(x) = 30(1.05)^x and L(x) = 30 + 2x.
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\n" ); document.write( "I need to give an example of a value x when L(x) < E(x). Can someone please help? I am really struggling with this one. I have the rest of the problem figured out.
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Algebra.Com's Answer #428756 by KMST(5328)\"\" \"About 
You can put this solution on YOUR website!
\"L%28x%29+=+30+%2B+2x\" is a cleverly named \"highlight%28L%29\"inear function, while
\n" ); document.write( "\"E%28x%29+=+30%281.05%29%5Ex\" is a cleverly named \"highlight%28E%29\"xponential function.
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\n" ); document.write( "Linear functions graph as straight lines, and \"L%28x%29+=+30+%2B+2x\" represents a line with a slope of \"2\" throughout its all real numbers domain.
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\n" ); document.write( "Exponential functions graph as curved lines, and if the base is greater than one, as for \"E%28x%29+=+30%281.05%29%5Ex\", have \"exponential growth\" graphs that look like this \"graph%28200%2C200%2C-0.99%2C0.99%2C-0.99%2C0.99%2C0.2%2A2%5E%282x%29%29\", with slopes that increase from very small to very large.
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\n" ); document.write( "The line could be tangent to the exponential curve and the graphs could intersect at only one point, as in \"graph%28200%2C200%2C-0.99%2C0.99%2C-0.99%2C0.99%2C0.6x%2B0.18%2C0.2%2Ae%5E%282x%29%29\"
\n" ); document.write( "Otherwise, a linear curve and an exponential curve could intersect at two points \"graph%28200%2C200%2C-0.99%2C0.99%2C-0.99%2C0.99%2C0.3x%2B0.3%2C0.2%2A2%5E%282x%29%29\", or zero points \"graph%28200%2C200%2C-0.99%2C0.99%2C-0.99%2C0.99%2C0.3x%2B0.1%2C0.2%2A2%5E%282x%29%29\".
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\n" ); document.write( "In any of those cases, the line is below the exponential curve (\"L%28x%29+%3C+E%28x%29\") at most (if not all) points, for most (if not all) values of \"x\".
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\n" ); document.write( "Which of those scenarios is the case for your functions?
\n" ); document.write( "\"L%280%29=30%2B2%2A0=30%2B0=30\" and
\n" ); document.write( "\"E%280%29=30%281.05%29%5E0=30%2A1=30\", so the graphs intersect at a least one point, with \"x=0\".
\n" ); document.write( "We can look at points to either side.
\n" ); document.write( "If the curves are tangent at \"x=0\", for all other values of \"x\"
\n" ); document.write( "it will be (\"L%28x%29+%3C+E%28x%29\".
\n" ); document.write( "If the curves are not tangent at \"x=0\", then they intersect at two points,
\n" ); document.write( "In that case, \"L%28x%29%3CE%28x%29\" will be true at least in some interval to one side of \"x=0\", and we may be lucky enough to find a point there.
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\n" ); document.write( "For \"x=1\":
\n" ); document.write( "\"L%281%29=30%2B2%2A1=30%2B2=32\" and
\n" ); document.write( "\"E%281%29=30%281.05%29%5E1=30%2A1.05=31.5\" so for \"x=1\", \"L%28x%29%3EE%28x%29\"
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\n" ); document.write( "For \"x=-1\":
\n" ); document.write( "\"L%28-1%29=30%2B2%2A%28-1%29=30-2=28\" and
\n" ); document.write( "\"E%281%29=30%281.05%29%5E%28-1%29=30%2F1.05=200%2F7\"=approx.\"28.57\" so for \"highlight%28x=-1%29\", \"L%28x%29%3CE%28x%29\"
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