document.write( "Question 696004: Jessica made anut mixture that contains 72% peanuts by mixing 14kg of mixed nuts with 11 kg of peanuts. The mixed nuts contained what percent peanuts?
\n" ); document.write( "---
\n" ); document.write( "I somewhat understand the problem, but I don't know how to set up a plausible equation.
\n" ); document.write( "Please help! \n" ); document.write( "

Algebra.Com's Answer #428746 by solver91311(24713) $\"\"$ $\"About$

You can put this solution on YOUR website!
\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "There are 25 kg of nuts total (14 + 11). Since the mixture contains 72% peanuts, then there must be 0.72 times 25 = 18 kg of peanuts. 11 kg of those 18 kg come from the 11 kg of peanuts, so 7 kg (18 minus 11) of the peanuts came from the 14 kg of mixed nuts. 7 is 50% of 14. \r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "John
\n" ); document.write( "

\n" ); document.write( "Egw to Beta kai to Sigma
\n" ); document.write( "My calculator said it, I believe it, that settles it
\n" ); document.write( "

$\"The$

\n" ); document.write( " \n" ); document.write( "

\n" );