document.write( "Question 695964: I have to put this in standard form....
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document.write( "3a+b-2=b\r
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document.write( "Thank you! \n" );
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Algebra.Com's Answer #428725 by jim_thompson5910(35256)![]() ![]() ![]() You can put this solution on YOUR website! 3a+b-2=b \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "3a+b-2-b = 0\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "3a + 0b - 2 = 0\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "3a + 0b = 2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So if a and b are your variables, then standard form would be ka + mb = n where k, m, n are fixed numbers. So because 3a + 0b = 2 fits that form, 3a + 0b = 2 is in standard form. \n" ); document.write( " |