document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=48607>Question 48607</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A candy store owner wishes to mix candy that sells for $3 per pound with candy selling for $4 per pound to make a mixture to sell for $3.60 per pound.  How many pounds of each kind of cany should be used to  make an 80 pound mixture?\r<BR>\n" );
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document.write( "Thank you </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #42872 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=42872\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x=amount selling for $3 per lb<BR>\n" );
document.write( "Then 80-x=amount selling for $4 per lb\r<BR>\n" );
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document.write( "Now we know that the total amount of dollars generated by selling the candy separately would have to equal the total amount of dollars generated by selling the 80 lb mixture.  Therefore, our equation to solve is:\r<BR>\n" );
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document.write( "$3x+(80-x)($4)=(80)($3.60) simplifying, we get:<BR>\n" );
document.write( "3x+320-4x=288<BR>\n" );
document.write( "-x=-32 or<BR>\n" );
document.write( "x=32 lb of $3 candy<BR>\n" );
document.write( "80-x=80-32=48 lb of $4 candy\r<BR>\n" );
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document.write( "Hope this helps -----ptaylor\r<BR>\n" );
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