document.write( "Question 695883: Jerry is 5 times as old as Hannah. In 2 years, he will be 3 times as old, and in 6 years, he'll only be twice as old.
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document.write( "How old will Jerry be in 6 years time? \n" );
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Algebra.Com's Answer #428698 by Stitch(470)![]() ![]() ![]() You can put this solution on YOUR website! Let A = Jerry's current age \n" ); document.write( "Let B = Hannah's current age \n" ); document.write( "Equation 1: \n" ); document.write( "Equation 2: \n" ); document.write( "Equation 3: \n" ); document.write( "-------------------------------- \n" ); document.write( "Plug 5B into equation 2 for A \n" ); document.write( "Equation 2: \n" ); document.write( " \n" ); document.write( "Simplify \n" ); document.write( " \n" ); document.write( "Subtract 3B from both sides \n" ); document.write( " \n" ); document.write( "Subtract 2 from both sides \n" ); document.write( " \n" ); document.write( "Divide both sides by 2 \n" ); document.write( " \n" ); document.write( "Now plug 2 into equation 1 for B \n" ); document.write( "Equation 1: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "So if Jerry is ten now then in 6 years he will be 16. \n" ); document.write( " \n" ); document.write( " |